1/2x^2=80

Solution for 1/2x^2=80 equation:

1/2x^2=80

We move all terms to the left:

1/2x^2-(80)=0


Domain of the equation: 2x^2!=0

x^2!=0/2

x^2!=√0

x!=0

x∈R


We multiply all the terms by the denominator


-80*2x^2+1=0

Wy multiply elements

-160x^2+1=0

a = -160; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-160)·1
Δ = 640
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{640}=\sqrt{64*10}=\sqrt{64}*\sqrt{10}=8\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{10}}{2*-160}=\frac{0-8\sqrt{10}}{-320}
=-\frac{8\sqrt{10}}{-320}
=-\frac{\sqrt{10}}{-40}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{10}}{2*-160}=\frac{0+8\sqrt{10}}{-320}
=\frac{8\sqrt{10}}{-320}
=\frac{\sqrt{10}}{-40}
$